In the colorimetric determination of cholesterol using the enzyme cholesterol oxidase, which agent oxidizes the colorless organic compound 4-aminoantipyrine to a pink complex?

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Multiple Choice

In the colorimetric determination of cholesterol using the enzyme cholesterol oxidase, which agent oxidizes the colorless organic compound 4-aminoantipyrine to a pink complex?

Explanation:
In this colorimetric cholesterol assay, the essential step is the production of hydrogen peroxide when cholesterol is oxidized by cholesterol oxidase. That hydrogen peroxide then acts as the oxidant in a peroxidase-catalyzed reaction that uses 4-aminoantipyrine and phenol to form a pink chromogen. The pink color arises from the oxidized form of 4-aminoantipyrine, produced specifically by the action of hydrogen peroxide in the presence of peroxidase. Cholest-4-en-3-one is simply the oxidation product of cholesterol, not the dye-forming agent; NAD is not involved in this pathway; phenol participates in the dye formation but does not provide the oxidizing power. Therefore, hydrogen peroxide is the agent that oxidizes 4-aminoantipyrine to the pink complex.

In this colorimetric cholesterol assay, the essential step is the production of hydrogen peroxide when cholesterol is oxidized by cholesterol oxidase. That hydrogen peroxide then acts as the oxidant in a peroxidase-catalyzed reaction that uses 4-aminoantipyrine and phenol to form a pink chromogen. The pink color arises from the oxidized form of 4-aminoantipyrine, produced specifically by the action of hydrogen peroxide in the presence of peroxidase. Cholest-4-en-3-one is simply the oxidation product of cholesterol, not the dye-forming agent; NAD is not involved in this pathway; phenol participates in the dye formation but does not provide the oxidizing power. Therefore, hydrogen peroxide is the agent that oxidizes 4-aminoantipyrine to the pink complex.

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